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node

有个函数数组的问题,一下子没想到法子,问问大家

  •  
  •   node · Apr 25, 2014 · 3764 views
    This topic created in 4390 days ago, the information mentioned may be changed or developed.
    var aaa = [];
    aaa[0] = func_x;
    aaa[1] = func_y;
    ...

    var bbb = [];

    如果我希望像这样定义bbb里面的函数:
    bbb[0] = function() {
    ...
    aaa[0]();
    ...
    };

    这个bbb函数定义的循环应该怎么写?
    Supplement 1  ·  Apr 25, 2014
    修改一下,方便能辨识结果

    bbb[0] = function(x) {
    ...
    aaa[0](x);
    ...
    };
    3 replies    1970-01-01 08:00:00 +08:00
    jakwings
        1
    jakwings  
       Apr 25, 2014   ❤️ 1
    Google一下「闭包函数」受到启发后记得给我一个赞。
    pubby
        2
    pubby  
       Apr 25, 2014   ❤️ 1
    var i;
    var mkf = function(arr,idx){
    return function(){
    arr[idx]();
    };
    };
    for(i=0;i<aaa.length;i++){
    bbb.push(mkf(aaa,i));
    }
    node
        3
    node  
    OP
       Apr 26, 2014
    @jakwings
    @pubby
    脑袋的stack over flow了,之前想到partial的时候套了几层没套出来,多谢啦
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