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luefei
V2EX  ›  MySQL

求教 mysql 查询语句。mysql 数据格式如下,表中 app 重复。需求:取出 一段时间内(四天内吧) 每天每个 appid 调用总量( count 总量)最大的前两个 appid

  •  
  •   luefei · 2015-10-26 10:33:47 +08:00 · 3707 次点击
    这是一个创建于 3309 天前的主题,其中的信息可能已经有所发展或是发生改变。

    logtime appid count
    100018 1226461
    1002495 6165611
    2015-10-1 1000255 156164611
    100018 4964610
    1002495 16461661
    1000255 46461168

    100018      196494561
                1002495     416461616
                1000255     616113
    

    2015-10-2 100018 16461131
    1002495 16461613
    1000255 1641351

    100018      2646116
                1002495     6116161
                1000255     126461611
    

    2015-10-3 100018 548531
    1002495 54136116
    1000255 496811

    100018      41646161
                1002495     1644131
                1000255     61164611
    

    2015-10-4 100018 443134
    1002495 15133
    1000255 1641434

    27 条回复    2015-10-27 08:14:30 +08:00
    luefei
        1
    luefei  
    OP
       2015-10-26 10:35:19 +08:00
    。。。这个格式。。好蛋疼。。
    luefei
        2
    luefei  
    OP
       2015-10-26 10:35:33 +08:00
    logtime appid count
    100018 1226461
    1002495 6165611
    2015-10-1 1000255 156164611
    100018 4964610
    1002495 16461661
    1000255 46461168

    100018 196494561
    1002495 416461616
    1000255 616113
    2015-10-2 100018 16461131
    1002495 16461613
    1000255 1641351

    100018 2646116
    1002495 6116161
    1000255 126461611
    2015-10-3 100018 548531
    1002495 54136116
    1000255 496811

    100018 41646161
    1002495 1644131
    1000255 61164611
    2015-10-4 100018 443134
    1002495 15133
    1000255 1641434
    luefei
        3
    luefei  
    OP
       2015-10-26 10:45:07 +08:00
    logtime appid count
    100018 1226461
    1002495 6165611
    2015-10-1 1000255 156164611
    100018 4964610
    1002495 16461661
    1000255 46461168

    100018 196494561
    1002495 416461616
    1000255 616113
    2015-10-2 100018 16461131
    1002495 16461613
    1000255 1641351

    100018 2646116
    1002495 6116161
    1000255 126461611
    2015-10-3 100018 548531
    1002495 54136116
    1000255 496811

    100018 41646161
    1002495 1644131
    1000255 61164611
    2015-10-4 100018 443134
    1002495 15133
    1000255 1641434 这样的格式 讲究下吧,各位大牛求指导。
    herojaxy
        4
    herojaxy  
       2015-10-26 10:46:59 +08:00
    这排版...没看懂啥意思
    luefei
        5
    luefei  
    OP
       2015-10-26 11:08:44 +08:00
    @herojaxy 额 数据格式三列 日期 appid 调用量, 结果 发出去后 日期那一列就合进去了。第一次发问。不知道怎么发图片。尝试了两次 这个格式都没调整对。
    bugsnail
        6
    bugsnail  
       2015-10-26 12:49:57 +08:00   ❤️ 1
    表名,字段名,必须
    数据一行就可以了,只是为了形式
    关开格式的问题,不单单只能用空格的,你可以把空格替换成--再发上来都可以.....

    最后,自行 google V2EX 发图 ....
    HanSonJ
        7
    HanSonJ  
       2015-10-26 13:01:02 +08:00
    select count(appid) from table where time > 4days group by appid limit 2 order by count(appid) desc
    这样取出最大两个的总数,大概就这意思,不知道符不符合
    luefei
        8
    luefei  
    OP
       2015-10-26 14:54:52 +08:00
    @bugsnail 谢谢。我重新整理下
    luefei
        9
    luefei  
    OP
       2015-10-26 14:56:23 +08:00
    @HanSonJ 这样是没有调用总量的。调用总量 还要求和。
    luefei
        10
    luefei  
    OP
       2015-10-26 14:57:59 +08:00
    @bugsnail
    logtime appid count
    ------------100018 1226461
    ------------1002495 6165611
    2015-10-1 1000255 156164611
    100018 4964610
    1002495 16461661
    1000255 46461168

    100018 196494561
    1002495 416461616
    1000255 616113
    2015-10-2 100018 16461131
    1002495 16461613
    1000255 1641351

    100018 2646116
    1002495 6116161
    1000255 126461611
    2015-10-3 100018 548531
    1002495 54136116
    1000255 496811

    100018 41646161
    1002495 1644131
    1000255 61164611
    2015-10-4 100018 443134
    1002495 15133
    1000255 1641434
    luefei
        11
    luefei  
    OP
       2015-10-26 15:02:40 +08:00
    logtime appid count
    ------------ ------100018 1226461
    -------------------1002495 6165611
    2015-10-1 1000255 156164611
    -------------------100018 4964610
    -------------------1002495 16461661
    -------------------1000255 46461168

    -------------------100018 196494561
    -------------------1002495 416461616
    -------------------1000255 616113
    2015-10-2 100018 16461131
    -------------------1002495 16461613
    -------------------1000255 1641351

    -------------------100018 2646116
    -------------------1002495 6116161
    -------------------1000255 126461611
    2015-10-3 100018 548531
    -------------------1002495 54136116
    -------------------1000255 496811

    -------------------100018 41646161
    -------------------1002495 1644131
    -------------------1000255 61164611
    2015-10-4 100018 443134
    -------------------1002495 15133
    -------------------1000255 1641434
    popok
        12
    popok  
       2015-10-26 15:05:34 +08:00
    @luefei 你还是直接图片随便上传一个地方,贴图片地址吧
    iyaozhen
        13
    iyaozhen  
       2015-10-26 15:07:55 +08:00
    取 4 天?每天的调用量最大的 2 个?
    popok
        14
    popok  
       2015-10-26 15:17:05 +08:00
    select sum(count) from 表名 group by appid where logtime>2015-10-20 and logtime<2015-10-24 limit 0,2

    我猜是这样,没测试过
    popok
        15
    popok  
       2015-10-26 15:20:56 +08:00
    select sum(count) from 表名 where logtime>2015-10-20 and logtime<2015-10-24 group by appid order by sum(count) desc limit 0,2
    luefei
        16
    luefei  
    OP
       2015-10-26 15:24:54 +08:00
    @popok 恩恩。我看下重发个问题吧。这个第一次提问,搞砸了。。
    popok
        17
    popok  
       2015-10-26 15:26:42 +08:00
    @luefei 你的问题描述其实很简单,直接一个表头就说明白了,不需要截图了
    popok
        18
    popok  
       2015-10-26 15:41:04 +08:00
    select appid,sum(count) from 表名 where logtime>2015-10-20 and logtime<2015-10-24 group by appid order by 2 desc limit 0,2

    这个应该就是结果了
    bugsnail
        19
    bugsnail  
       2015-10-26 15:41:06 +08:00
    结构不知道是不是这样...
    ![]( http://7xiwkv.com1.z0.glb.clouddn.com/v2test.png)

    sql:

    ```
    select login_date,appid,count
    from t_name
    where UNIX_TIMESTAMP('2015-10-22') BETWEEN UNIX_TIMESTAMP(CURDATE())-3600*24*4 and UNIX_TIMESTAMP(CURDATE())
    group by login_date,appid
    order by login_date,count desc
    ```
    那个 22 号改为当前日期可以查看过去 4 天的,那个分组前两条不会了,请大神....
    luefei
        20
    luefei  
    OP
       2015-10-26 15:42:46 +08:00
    @popok 恩恩。算是比较复杂了。我写出来的语句 太复杂 效率太低 用不了。。所以还是请教帮忙,技术水平有限。 select a.* from (select logTime, appid, sum(count) as dailycount from table where datediff(current_date(), logTime) < 4 group by logTime, appid order by logTime, dailycount desc) as a where 2 > (select count(*) from (select logTime, appid, sum(count) as b from table where datediff(current_date(), logTime) group by logTime, appid order by logTime, dailycount desc) as b where a.logTime = b.logTime and b.dailycount > a.dailycount);
    popok
        21
    popok  
       2015-10-26 15:48:58 +08:00
    @luefei 好吧,你这个我看的晕,然后重新看了下主题,好像我理解错了
    tusj
        22
    tusj  
       2015-10-26 17:15:41 +08:00
    DROP TABLE IF EXISTS test.app_usage;
    CREATE TABLE test.app_usage
    (
    log_time DATETIME,
    app_id BIGINT,
    log_count BIGINT
    );

    DELETE FROM test.app_usage;
    INSERT INTO test.app_usage VALUES (NOW(), 123, 100);
    INSERT INTO test.app_usage VALUES (NOW(), 456, 200);
    INSERT INTO test.app_usage VALUES (NOW(), 789, 300);
    INSERT INTO test.app_usage VALUES (NOW(), 124, 100);
    INSERT INTO test.app_usage VALUES (NOW(), 234, 200);
    COMMIT;

    -- SELECT * FROM test.app_usage;
    SELECT a.*
    FROM (
    SELECT concat(DATE_FORMAT(log_time, '%Y%m%d'), app_id) AS group_key, MAX(date_format(log_time, '%Y%m%d')) as log_date, MAX(app_id), SUM(log_count) AS daily_count
    FROM test.app_usage
    WHERE DATEDIFF(CURRENT_DATE(), log_time) < 4
    GROUP BY group_key) AS a
    ORDER BY a.daily_count DESC
    LIMIT 0, 1;

    -- DROP TABLE IF EXISTS test.app_usage;
    luefei
        23
    luefei  
    OP
       2015-10-26 20:19:01 +08:00
    @popok 恩恩。需求略复杂。。智商捉急 所以请求大牛们帮忙解决。
    luefei
        24
    luefei  
    OP
       2015-10-26 20:21:14 +08:00
    @bugsnail 谢谢指导
    luefei
        25
    luefei  
    OP
       2015-10-26 20:26:14 +08:00
    @tusj 谢谢。这个语句 里的 sum(log_count) 是四天的调用量和,不是每天的 appid 求和。
    zeayes
        26
    zeayes  
       2015-10-26 23:14:55 +08:00
    USE test;
    DROP TABLE `test`;
    CREATE TABLE `test`(
    `logtime` DATETIME NOT NULL,
    `appid` VARCHAR(12) NOT NULL,
    `count` INT NOT NULL DEFAULT 0
    )DEFAULT CHARSET = UTF8;

    INSERT INTO `test` VALUES ('2015-10-15', '10001', 100);
    INSERT INTO `test` VALUES ('2015-10-15', '10001', 150);
    INSERT INTO `test` VALUES ('2015-10-15', '10001', 50);
    INSERT INTO `test` VALUES ('2015-10-15', '10003', 70);
    INSERT INTO `test` VALUES ('2015-10-15', '10002', 420);
    INSERT INTO `test` VALUES ('2015-10-15', '10002', 120);
    INSERT INTO `test` VALUES ('2015-10-15', '10002', 190);
    INSERT INTO `test` VALUES ('2015-10-16', '10001', 110);
    INSERT INTO `test` VALUES ('2015-10-16', '10001', 130);
    INSERT INTO `test` VALUES ('2015-10-16', '10001', 90);
    INSERT INTO `test` VALUES ('2015-10-15', '10002', 200);
    INSERT INTO `test` VALUES ('2015-10-16', '10003', 40);
    INSERT INTO `test` VALUES ('2015-10-16', '10003', 80);
    INSERT INTO `test` VALUES ('2015-10-16', '10003', 60);

    set @num := 0, @logtime := '';
    select logtime, appid, dailycount from (select a.logtime, a.appid, a.dailycount, @num := if(@logtime = date(a.logtime), @num + 1, 1) as row_number, @logtime := a.logtime from (select logtime, appid, sum(count) as dailycount from test group by logtime, appid order by logtime desc, dailycount desc) as a) as b where b.row_number < 3;


    http://www.xaprb.com/blog/2006/12/07/how-to-select-the-firstleastmax-row-per-group-in-sql/
    tusj
        27
    tusj  
       2015-10-27 08:14:30 +08:00 via Android
    @luefei 我给的就是按每天,每个 app_id 汇总的啊
    不然你觉得 group by 拿来干什么吃的呢?
    可能是你被 limit0,1 迷惑了,你把 limit 去掉就看明白了
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