Python 获取 HTTP 请求的状态码(200,404 等)

[donglongtu]

Python 获取 HTTP 请求的状态码(200,404 等),不访问整个页面源码，那样太浪费资源：

输入：www.v2ex.com 输出：200
输入：www.v2ex.com/nonexistant 输出：404

[revotu]

Python 实用脚本清单 : http://www.revotu.com/python-practical-script-list.html

http 不只有 get 方法（请求头部+正文），还有 head 方法，只请求头部。


import httplib

def get_status_code(host, path="/"):
""" This function retreives the status code of a website by requesting
HEAD data from the host. This means that it only requests the headers.
If the host cannot be reached or something else goes wrong, it returns
None instead.
"""
try:
conn = httplib.HTTPConnection(host)
conn.request("HEAD", path)
return conn.getresponse().status
except StandardError:
return None

print get_status_code("www.v2ex.com") # prints 200
print get_status_code("www.v2ex.com", "/nonexistant") # prints 404

[bolide2005]

>>> import requests
>>> response = requests.get("http://www.baidu.com")
>>> print response.status_code
200

[dd99iii]

def get_status_code(url):
r = requests.head(url)
return r.status_code