Python 的 list 怎么匹配 json ?

[toyst]

genre_movie = '{"genres":[{"id":28,"name":"动作"},{"id":12,"name":"冒险"},{"id":16,"name":"动画"},{"id":35,"name":"喜剧"},{"id":80,"name":"犯罪"},{"id":99,"name":"纪录"},{"id":18,"name":"剧情"},{"id":10751,"name":"家庭"},{"id":14,"name":"奇幻"},{"id":36,"name":"历史"},{"id":27,"name":"恐怖"},{"id":10402,"name":"音乐"},{"id":9648,"name":"悬疑"},{"id":10749,"name":"爱情"},{"id":878,"name":"科幻"},{"id":10770,"name":"电视电影"},{"id":53,"name":"惊悚"},{"id":10752,"name":"战争"},{"id":37,"name":"西部"}]}'

genre_ids = [80, 9648, 53]

想匹配生成 genre_ids = [犯罪, 悬疑, 惊悚]

应该怎么写啊

[zenxds]

[x['name'] for x in genre_movie['genres'] if x['id'] in genre_ids]

[yin1999]

用 json 包解析一下，然后 for in 、map 随你挑

[thinkershare]

如果有大量的字典类型的需要处理的, 可以使用 easydict, 最好还是将数据清洗一下, 这样效率高一点
import json
from easydict import EasyDict;

genre_movie = '{"genres":[{"id":28,"name":"动作"},{"id":12,"name":"冒险"},{"id":16,"name":"动画"},{"id":35,"name":"喜剧"},{"id":80,"name":"犯罪"},{"id":99,"name":"纪录"},{"id":18,"name":"剧情"},{"id":10751,"name":"家庭"},{"id":14,"name":"奇幻"},{"id":36,"name":"历史"},{"id":27,"name":"恐怖"},{"id":10402,"name":"音乐"},{"id":9648,"name":"悬疑"},{"id":10749,"name":"爱情"},{"id":878,"name":"科幻"},{"id":10770,"name":"电视电影"},{"id":53,"name":"惊悚"},{"id":10752,"name":"战争"},{"id":37,"name":"西部"}]}'

movies=EasyDict(json.loads(genre_movie)).genres
genre_ids = [80, 9648, 53]
genre_names = [movie.name for movie in movies if movie.id in genre_ids]
print(genre_names)

[jsutfun]

<script src="https://gist.github.com/hlpureboy/637f657d70f9b349c6a1ac1748173dc1.js"></script>

[em70]

遍历+判断,存起来输出

[TimePPT]

import pandas as pd
import json

genre_movie = '{"genres":[{"id":28,"name":"动作"},{"id":12,"name":"冒险"},{"id":16,"name":"动画"},{"id":35,"name":"喜剧"},{"id":80,"name":"犯罪"},{"id":99,"name":"纪录"},{"id":18,"name":"剧情"},{"id":10751,"name":"家庭"},{"id":14,"name":"奇幻"},{"id":36,"name":"历史"},{"id":27,"name":"恐怖"},{"id":10402,"name":"音乐"},{"id":9648,"name":"悬疑"},{"id":10749,"name":"爱情"},{"id":878,"name":"科幻"},{"id":10770,"name":"电视电影"},{"id":53,"name":"惊悚"},{"id":10752,"name":"战争"},{"id":37,"name":"西部"}]}'

genre_ids = [80, 9648, 53]

data = json.loads(genre_movie)
df = pd.DataFrame(data=data["genres"])

genre_names = df[df["id"].isin(genre_ids)]["name"].to_list()

[hhhhhh123]

jsonpath

[kaiger]

import json

genre_movie = '{"genres":[{"id":28,"name":"动作"},{"id":12,"name":"冒险"},{"id":16,"name":"动画"},{"id":35,"name":"喜剧"},{"id":80,"name":"犯罪"},{"id":99,"name":"纪录"},{"id":18,"name":"剧情"},{"id":10751,"name":"家庭"},{"id":14,"name":"奇幻"},{"id":36,"name":"历史"},{"id":27,"name":"恐怖"},{"id":10402,"name":"音乐"},{"id":9648,"name":"悬疑"},{"id":10749,"name":"爱情"},{"id":878,"name":"科幻"},{"id":10770,"name":"电视电影"},{"id":53,"name":"惊悚"},{"id":10752,"name":"战争"},{"id":37,"name":"西部"}]}'

genre_movie_dict = json.loads(genre_movie)
genre_ids = [80, 9648, 53]
genre_name = [genre.get('name') for genre in genre_movie_dict.get('genres') if genre.get('id') in genre_ids]
print(genre_name)

[ALLROBOT]

可以用正则表达式匹配，比如 /"name:""([^"]*)"/，有几个 id 就 for in range(len(xx))逐次输入到 list

[youdoit]

初学者献丑，看看是不是这样

list_str = [] # 文字列表
list_int = [] # 数字列表

for k,v in genre_movie.items():
for i in v: # 循环 values,这也是一个字典
for key, values in i.items():
if type(values) is not int: # 判断值是否为整数类型,写入相应的 list 列表
list_str.append(values)
else:
list_int.append(values)

print(list_str, list_int)

[youdoit]

for k,v in genre_movie.items():
for i in v: # 循环 values,这也是一个字典
if i.get('id') in genre_ids: # 获取字典里的 id 值,并且存在列表里面
list_str.append(i.get('name')) # 输出对于的 id 值一样的数据到列表

print(list_str)

多看了一遍才发现是这样的题目，上面那个文不对题了。