@xuelang 我把你的英文复制了一遍，这是他的回复


To calculate the final temperature of the mixed water, we need to use the principle of heat transfer. Since no heat is added or lost to the environment (assuming ideal conditions), the total heat content of the system will remain constant.

Calculate the total heat content before mixing:
Heat content of 25-degree water: 3 glasses x 200 grams/glass x 25°C x 4.18 J/g°C = 62,700 J
Heat content of 26-degree water: 1 glass x 200 grams/glass x 26°C x 4.18 J/g°C = 21,776 J
Total heat content: 84,476 J
After mixing, the water will reach a common equilibrium temperature. Let's call this temperature "T".
Total heat content after mixing: 4 glasses x 200 grams/glass x T x 4.18 J/g°C = 836T J
Equate the heat contents before and after mixing: 84,476 J = 836T J => T = 84,476 J / 836 J/°C = 101°C
Therefore, the final temperature of the mixed water will be approximately 101°C.