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imcottonV2EX member #21296, joined on 2012-05-23 01:53:06 +08:00 |
| Free private GitHub repository 101 git • imcotton • May 23, 2012 • Lastly replied by imcotton | 9 |
imcotton's recent replies
Feb 23, 2017 Replied to a topic by Yourdaye › 互联网 › 互联网最糟糕的体验就是到处都需要注册==》登录！ |
Mozilla Replaces Persona with Auth0 for Identity and Access Management (IAM)
https://auth0.com/blog/auth0-mozilla-partnership/
Auth0 Passwordless
https://auth0.com/passwordless
https://auth0.com/blog/auth0-mozilla-partnership/
Auth0 Passwordless
https://auth0.com/passwordless
Dec 9, 2016 Replied to a topic by peterontheway › 问与答 › A + B 问题 |
// 371. Sum of Two Integers
// https://leetcode.com/problems/sum-of-two-integers/
/**
* @param {number} a
* @param {number} b
* @return {number}
*/
var getSum = function (a = 0, b = 0) {
while (a !== 0) {
[a, b] = [(a & b) << 1, a ^ b];
}
return b;
};
// https://leetcode.com/problems/sum-of-two-integers/
/**
* @param {number} a
* @param {number} b
* @return {number}
*/
var getSum = function (a = 0, b = 0) {
while (a !== 0) {
[a, b] = [(a & b) << 1, a ^ b];
}
return b;
};
May 3, 2016 Replied to a topic by PiedPiper › 酷工作 › hiring! just got invested! |
"I don't know about you people, but I don't want to live in a world where someone else makes the world a better place better than we do."
Feb 27, 2016 Replied to a topic by northisland › 问与答 › 出道题给大家耍下，有闲的各位请接招 |
'tt2012dg2'.match(/\d+/g).reduce((a, b) => a.length > b.length ? a : b)
-ES2015
-ES2015
Sep 4, 2014 Replied to a topic by muziyue › 问与答 › img 标签可以达到 background-size:cover 的效果么？ |
Sep 4, 2014 Replied to a topic by webjin › Linux › uptime 时间可以作假修改吗？ |
Sep 1, 2014 Replied to a topic by juo › 酷工作 › [北京] FIR.im 招聘 - 有的人找工作, 有的人换工作; 有些人, 会加入 FIR.im |
@juo 第二张照片里左起第二位手里捏着香烟？
Aug 14, 2014 Replied to a topic by georgetso › 问与答 › 请问有没有 RESTful API 请求测试的网站？ |
Aug 1, 2014 Replied to a topic by taoche › 程序员 › 请教一些 CoffeeScript 的问题 |
自己脑补上面最后两行的缩进吧
Aug 1, 2014 Replied to a topic by taoche › 程序员 › 请教一些 CoffeeScript 的问题 |
a = 1
b = 2
do ({a, b} = {}) ->
a = 3
b = 4
b = 2
do ({a, b} = {}) ->
a = 3
b = 4
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