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Kei001
V2EX  ›  问与答

请教一个树形结构扁平化算法

  •  
  •   Kei001 · 2022-06-06 22:35:19 +08:00 · 1089 次点击
    这是一个创建于 679 天前的主题,其中的信息可能已经有所发展或是发生改变。

    需要将以下树形结构转成扁平化数组,同时添加一个从父级到子级的路径数组。

    let tree = [
        {
            id: 1,
            title: "grandfather",
            children: [
                {
                    id: 3,
                    title: "father"
                },
                {
                    id: 4,
                    title: "father2",
                    children: [{
                        id: 6,
                        title: "child1"
                    }]
                }
            ]
        },
        {
            id: 2,
            name: "grandfather2",
            children: [{
                id: 5,
                name: "father3"
            }]
        }
    ];
    
    
    let list = [
        { id: 1, title: "grandfather", path: ['grandfather'] },
        { id: 3, title: "father", path: ['grandfather', 'father'] },
        { id: 4, title: "father2", path: ['grandfather', 'father2'] },
        { id: 6, title: "child1", path: ['grandfather', 'father2', 'child1'] },
        { id: 2, title: "grandfather", path: ['grandfather2'] },
        { id: 5, title: "father3", path: ['grandfather2', 'father3'] },
    ];
    

    递归问题实在有点让我头疼,没有能解出来,因此请教一下万能的 V 友有没有什么好的解法。

    8 条回复    2022-06-07 09:42:34 +08:00
    cpstar
        1
    cpstar  
       2022-06-06 22:51:54 +08:00
    深度优先遍历
    sharida
        2
    sharida  
       2022-06-06 22:55:17 +08:00   ❤️ 1
    递归
    ```javascript
    const res = [];
    function tree2list(tree, path = []) {
    for (let i = 0; i < tree.length; i++) {
    const item = tree[i];
    const p = [...path, item.title];
    res.push({ ...item, path: p });
    if (Array.isArray(item.children)) {
    cb(item.children, p);
    }
    }
    }
    ```
    cpstar
        3
    cpstar  
       2022-06-06 23:00:10 +08:00   ❤️ 1
    补充 1# 就是递归

    array list = [];
    func recursion(node, parent_path) {
    list.add({id: node.id, title: node.title, path: parent_path});
    for(let n in node.children)
    recursion(n, parent_path.add(n.title));
    }
    for (let t in tree) {
    recursion(t, [t.title]);
    }
    luob
        4
    luob  
       2022-06-06 23:23:21 +08:00   ❤️ 1
    来点函数式

    const h = (list, paths, sum) => list.reduce((acc, { id, title, children }) => ([...acc, { id, title, paths: [...paths, title] }, ...h(children || [], [...paths, title], [])]), sum);

    const flat = (tree) => h(tree, [], []);
    rabbbit
        5
    rabbbit  
       2022-06-06 23:36:42 +08:00   ❤️ 1
    const flat = (children) => {
      const pathMap = new Map(children.map((i) => [i.id, [i.title]]));
      const list = [...children];
      const result = [];
      while (list.length > 0) {
       const { id, title, children } = list.shift();
       const path = pathMap.get(id);
       result.push({ id, title, path });
       if (children) {
        list.unshift(...children);
        children.forEach((i) => pathMap.set(i.id, [...path, i.title]));
      }
     }
      return result;
    };
    wunonglin
        6
    wunonglin  
       2022-06-06 23:38:53 +08:00   ❤️ 1
    Kei001
        7
    Kei001  
    OP
       2022-06-07 09:38:50 +08:00
    @sharida @cpstar @luob @rabbbit @wunonglin 感谢,解决了!
    Kei001
        8
    Kei001  
    OP
       2022-06-07 09:42:34 +08:00
    @wunonglin 第二个父节点的 title 不小心写成了 name ,没想到你也考虑到了,哈哈 感谢!
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