这是一个创建于 839 天前的主题，其中的信息可能已经有所发展或是发生改变。
表是这样的：
| id | uid | type | num |
|---|---|---|---|
| 1 | 1 | 0 | 24 |
| 2 | 2 | 2 | 21 |
| 3 | 3 | 1 | 14 |
| 4 | 1 | 0 | 24 |
| 5 | 2 | 2 | 21 |
| 6 | 3 | 1 | 14 |
按 uid 分组，然后根据 type 类型对 num 进行汇总，type 是固定的，一共有三种，这种应该怎么写呢？
结果大概这样： [ { uid: 1, type_0_sum: 10, type_1_sum: 12, type_2_sum: 12 }, { uid: 2, type_0_sum: 10, type_1_sum: 12, type_2_sum: 12 }, { uid: 3, type_0_sum: 10, type_1_sum: 12, type_2_sum: 12 }, ]
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1
sadfQED2 2022-08-11 15:03:56 +08:00 via Android
select uid,type,sum(num) from xxxx group by uid,type
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2
ThunderMonkey 2022-08-11 15:06:09 +08:00
SELECT
uid, sum(case when type = 0 then num else 0 end) as type_0, sum(case when type = 1 then num else 0 end) as type_1, sum(case when type = 2 then num else 0 end) as type_2 FROM table group by uid |
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3
Danswerme OP |
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