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Suclogger

V2EX 第 71444 号会员,加入于 2014-08-20 16:59:05 +08:00
今日活跃度排名 1257
Suclogger 最近回复了
再贴一段来自:Osiris Jailbreak 的解释:
这个东西可以实现什么:
What can it do?
1. 降级到任意系统版本
Tethered downgrades without SHSH2 blobs to any supported version. SEP may be a problem with this even with this exploit, I need to check.
2. 导出 SecureROM
Dumping the SecureROM (dumps the bootroom itself for research purposes).
3. 加载任何自定义的固件(这个是我最感兴趣的)
Load a custom firmware (CFW) for any purpose: jailbreak, activation, custom Apple logo, verbose boot, etc.
4. 在任意系统版本上实现越狱
Jailbreak the latest signed firmware tethered (needs a computer for every boot, even for stock).
5. 修复越狱引入的问题
Load an SSH ramdisk and fix a bootloop caused by the removal of files during Jailbreak.
6. 类似双系统
DualBoot iOS versions tethered.
7. 在 ios 设备上运行 android ( XD )
Possibly port and run Linux or Android (requires huge amounts of work)
8. 各种安全研究
Do security research and patch ANY security feature Apple introduces in Software on the newer iOS versions.
9. 绕过各种安全策略
Give no hecks about KPP / KTRR, AMFI, CoreTrust and such. No more clumsy patches but tethered.
@kljsandjb #7 #7 嗯,看到有人说:

>This is tethered, not untethered as some people say on this sub-reddit. This means anything from Downgrades to activation to Jailbreak made with this would be tethered forever. Tethered = you need to run ipwndfu software on the computer with the phone in DFU mode everytime you wanna power on your device, otherwise it would not even boot to stock. Much more annoying than the semi-tethered jailbreaks of today.

貌似只能做到 tethered,每次启动需要重新引导
@bookit #3 #3 原作者回复:

>Maybe someone can figure out a nice way to use JTAG on iPhone without proprietary hardware and software. I and many others would be forever grateful if someone makes that possible.

获取将来无需硬件设备也未可知
@kljsandjb #2 #2 个人感觉,这个东西的意义在于,不受系统版本限制的越狱,是不是完美越狱,取决于如何在他的基础上二次开发
@laoyur #1 #1 貌似没搜到,被降权了么
190 天前
回复了 appgle 创建的主题 2019 百度网盘团队提前庆祝国庆
壁纸好评
看代码刷评论的上下楼兄弟岂不是被连坐 assert 了
现在靠 aria2 全搞定,接管浏览器,接管百度云盘,也支持 BT
@yinqi025 #43 #43 之前有朋友买过,价格比你这贵一些,可以加 wx py,之前对这个也比较感兴趣,同 id
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